Carlwarker
24-09-2003, 17:07
Two missiles speed directly toward each other, one at 9,000 mph and the other at 21,000 mph. The start 1,767 miles apart. Without using pencil and paper, calculate how far apart they are one minute before they collide.
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View Full Version : Another teaser Carlwarker 24-09-2003, 17:07 Two missiles speed directly toward each other, one at 9,000 mph and the other at 21,000 mph. The start 1,767 miles apart. Without using pencil and paper, calculate how far apart they are one minute before they collide. Jamie 24-09-2003, 17:15 500 miles ? doesn't matter how far apart they are to begin with (unless they are closer than on minute apart). thier combined speed is 30,000 miles per hour. 60 minutes in one hour. 30 / 60 = .5 ... thus 500 miles ? Carlwarker 24-09-2003, 17:17 You're a good'n jamieW! max 24-09-2003, 17:24 Without doing sums or writing anything down answer me this: In a knockout tennis tournament of 259 players how many matches will have been played to determine the winner? Carlwarker 24-09-2003, 17:58 One I guess. Although with 259 players and assuming singles play there would be a total of 278 matches with 5 byes, including a bye into the final. Jamie 24-09-2003, 20:15 Damn it !!! they get harder :o 258 ... I agree with you Carl. Although I would have no 'byes' ... instead I have 6 un-seeded players and 253 seeded players. The un-seeded players play off in 3 games to leave 3 ... added to the 253 seeded = 256 players for round 2 ... To get from 256 to 1 takes 255 games using binary subdivision. 256 to 128 = 128 games ... 128 to 64 = 64 games ... 64 to 32 = 32 games ... 32 to 16 = 16 games ... basically from 256 to 1 is (256 - 1) ... 255 + 3 = 258. Carlwarker 24-09-2003, 20:24 Yessir - although from what I remember of my 'Parks League' games in the 50's and 60's, in a real tournament you do have byes. It's interesting that with there being 3 more than a power of 2 in the tournament (256 +3) that the 'final is between 3 players - hence the last bye in the semi. This one reminded me of the old ' when I was going to St. Ives... Jamie 24-09-2003, 20:34 I like your signature Carl :) Carlwarker 24-09-2003, 20:50 Thanks jamieW. Here's my synopsis of the tennis tournament: 1st round: 129 matches + 1 bye 2nd round: 75 3rd round: 37 + 1 4th round: 19 5th round 9 + 1 6th round 5 7th round 2 + 1 8th round 1 + 1 9th round Final Total 278 matches Hence, with byes, a total of 278 matches. Jamie 24-09-2003, 21:17 I'm confused !! How did you get 75 matches for the second round ... should it not be 65 ? (130 players gone through from the first round). Carlwarker 24-09-2003, 21:32 I hang my head in shame - **** - I AM getting old or senile or both or stoned! My humble apologies. It is, of course: 129+1 65 32+1 16+1 8+1 4+1 2+1 1+1 1 Final Total: 258 Please forgive an idiot who can't divide by two. The only excuse I can give is that I did follow the instructions and did it in my head. Carlwarker 24-09-2003, 21:37 NOT Henman! max 25-09-2003, 07:37 The simple answer is that in a knockout everybody except the winner gets knocked out. So, in a competition of 259 people 258 people get knocked out therefore 258 matches have to be played. Note, matches not byes. The same goes for any number: 715 players, 714 losers therefore 714 matches. I did say no sums and no writing down. nomme 25-09-2003, 09:01 Originally posted by max The simple answer is that in a knockout everybody except the winner gets knocked out. So, in a competition of 259 people 258 people get knocked out therefore 258 matches have to be played. Note, matches not byes. The same goes for any number: 715 players, 714 losers therefore 714 matches. I did say no sums and no writing down. Damn. You bet me to it. I figured it out as I was eating my breakfast this morning. Nomme max 25-09-2003, 09:20 Originally posted by nommedenet Damn. You beat me to it. I figured it out as I was eating my breakfast this morning. Nomme Sorry, I thought 14 hours was long enough to leave it un-answered. I'll think of another one and leave it longer. nomme 25-09-2003, 09:32 Originally posted by max Sorry, I thought 14 hours was long enough to leave it un-answered. I'll think of another one and leave it longer. Yeah..... but those 14 hours included the average 8 most of us get some kip!! Anyway - any good at cryptic crossword clues? If you *know* the answers to these straight off please refrain from posting the answers (i.e spoiling it for others who haven't seen them before), but if you figure them out then by all means show how clever you are. Here's some of my favourites : 1) HIJKLMNO (5) 2) GEGS (9,5) 3) E (13) Nomme Carlwarker 25-09-2003, 09:34 Originally posted by max The simple answer is that in a knockout everybody except the winner gets knocked out. So, in a competition of 259 people 258 people get knocked out therefore 258 matches have to be played. Note, matches not byes. The same goes for any number: 715 players, 714 losers therefore 714 matches. I did say no sums and no writing down. It could also be argued semantically that only ONE match actually determines the winner! Hence the 'St. Ives' analogy. max 25-09-2003, 09:43 Originally posted by Carlwarker It could also be argued semantically that only ONE match actually determines the winner! Hence the 'St. Ives' analogy. Yeah, I spotted that in one of your earlier posts but you still had to use sums and writing down to get the right answer, eventually. Carlwarker 25-09-2003, 09:54 Originally posted by max Yeah, I spotted that in one of your earlier posts but you still had to use sums and writing down to get the right answer, eventually. If you look at my postings you'll find that I DID NOT use pencil or paper or a calculator - except the old 'bonce' - which did let me down at one stage (130/2 = 75 !!!!!! idiot me). And thanks to JamieW, I did correct the arithmetical error, again solely with the old grey matter. ps. Keep 'em coming Max. max 25-09-2003, 10:02 Originally posted by Carlwarker If you look at my postings you'll find that I DID NOT use pencil or paper or a calculator - except the old 'bonce' - which did let me down at one stage (130/2 = 75 !!!!!! idiot me). And thanks to JamieW, I did correct the arithmetical error, again solely with the old grey matter. ps. Keep 'em coming Max. OK, apologies for implying that. However, the point of that teaser was that you didn't need to do any sort of calculations as it was a logic problem not a maths one. Jamie 25-09-2003, 10:05 I love max's solution to the tennis tournament :) It's funny how human beings can have a tendency to make things more complex than they need to be ... or to look for more complex solutions !! I'm guilty of being too complex loads ... mind you ... it wouldn't look good if people called me simple :o Jamie 25-09-2003, 10:09 Originally posted by Carlwarker If you look at my postings you'll find that I DID NOT use pencil or paper or a calculator - except the old 'bonce' - which did let me down at one stage (130/2 = 75 !!!!!! idiot me)... What amazes me is that you got the 75 .. 37 .. etc .. and after adding up all games played in each round ... you still got 258 !!! Pure class lol !!! Carlwarker 25-09-2003, 10:23 Thanks JamieW - but I did make that damn error - and at my age that's worrying! Guess I'll just have to check and re-check next time (should do that anyway). Jamie 25-09-2003, 12:07 How about this one ... with no pencils / paper / calculators ... There once was a salmon who tried to swim upstream to the place where she was born. She had to swim 1,010 feet upstream to reach the shady pool of water where she had once hatched from her egg. Every five minutes she swam 30 feet upstream, but then in the next two minutes, while she rested,the rushing current would push her 10 feet back downstream. She continued this way, swimming for five minutes then resting for two minutes, until she reached her destination. How long did it take her to swim the entire 1,010 feet? Zamo 25-09-2003, 12:20 5hr 48 minutes. Jamie 25-09-2003, 12:32 Boy you were fast Zamo :) Correct !!! ... 348 minutes (= 5hr 48mins) 50 x 30 feet (1500 feet) - 49 x 10 feet (490 feet) = 1010 feet 50 x 5 mins (250 mins) + 49 x 2 mins (98 mins) = 348 mins ... Zamo 25-09-2003, 12:37 Phew!!! Almost got caught out by including a 2 minute rest at the end! Tony Ruscoe 25-09-2003, 12:38 Originally posted by max The simple answer is that in a knockout everybody except the winner gets knocked out. So, in a competition of 259 people 258 people get knocked out therefore 258 matches have to be played. Note, matches not byes.I was taught this as part of my General Studies A-Level course :) Carlwarker 25-09-2003, 13:11 Another way of reasoning is that the salmon goes 20 ft upstream every 7 minutes which gives 980 ft in 343 min, plus 5 min for the last 30 ft. Guess there was no 'catch' involved in that teaser! (groan). nomme 25-09-2003, 13:19 Originally posted by Carlwarker Another way of reasoning is that the salmon goes 20 ft upstream every 7 minutes which gives 980 ft in 343 min, plus 5 min for the last 30 ft. Guess there was no 'catch' involved in that teaser! (groan). Yeah - that's how I figured it out. How about this one then : The son of a rich bullion merchant left home on the death of his father. All he had with him was a gold chain that consisted of 114 links. He rented a place in the city center with a shop at the lower level and an apartment at the upper level. He was required to pay every week one link of the gold chain as rent for the place. The landlady told him that she wanted one link of the gold chain at the end of one week, two gold links at the end of two weeks, three gold links at the end of three weeks and so on. The son realized that he had to cut the links of the gold chain to pay the weekly rent. If the son wished to rent the place for 114 weeks, what would be the minimum number of links he would need to cut? (You may use pen/paper/calculators/slide rules!!) Nomme max 25-09-2003, 13:30 (114 + 1) * 114/2 = 6555 However if he only had 114 links it would run out after 2 weeks (14 + 1) * 14/2 = 105 Belle 25-09-2003, 13:45 Originally posted by nommedenet Yeah..... but those 14 hours included the average 8 most of us get some kip!! Anyway - any good at cryptic crossword clues? If you *know* the answers to these straight off please refrain from posting the answers (i.e spoiling it for others who haven't seen them before), but if you figure them out then by all means show how clever you are. Here's some of my favourites : 1) HIJKLMNO (5) 2) GEGS (9,5) 3) E (13) Nomme The first one is water - H to O or H little2 O (chemical symbol for water) The second one and the third one I am still pondering Belle 25-09-2003, 13:49 hurray, I have the second one too now Scrambled EGGS! third one looking tricky though....thinking E for emergency E for England E for errrrrrrrrrrrr Jamie 25-09-2003, 14:47 Nomminenmenendentenam ... Is the answer 4 ? Carlwarker 25-09-2003, 15:01 Originally posted by LouiseB hurray, I have the second one too now Scrambled EGGS! third one looking tricky though....thinking E for emergency E for England E for errrrrrrrrrrrr E for vescence! Belle 25-09-2003, 15:03 Originally posted by Carlwarker E for vescence! That cant be right, not enough letters Still scratching my head......... Belle 25-09-2003, 15:10 I wonder if there is a place with 13 letters in its name to be found at E13? My knowledge of the east end is shocking but it looks like West Ham I cant spend all night worrying about this Nomme, please put me out of my misery nomme 25-09-2003, 15:29 Originally posted by JamieW Nomminenmenendentenam ... Is the answer 4 ? Yes. Now explain your answer..... nomme 25-09-2003, 15:34 Originally posted by LouiseB I wonder if there is a place with 13 letters in its name to be found at E13? My knowledge of the east end is shocking but it looks like West Ham I cant spend all night worrying about this Nomme, please put me out of my misery Well I'll just give the others some more time. I've PM you the answer. Nomme Belle 25-09-2003, 15:37 Originally posted by nommedenet Well I'll just give the others some more time. I've PM you the answer. Nomme Thanks, I have read it and I would never have got it in a million years Keep up the good work posing them though Louise xxxxxxxxxxxxx Belle 25-09-2003, 15:42 Incidentally what I really like best is a bit of lateral thinking....got any puzzles like that up your sleeve, guys and gals? Carlwarker 25-09-2003, 16:04 Originally posted by LouiseB That cant be right, not enough letters Still scratching my head......... I WAS joking - it' from the old alphabet ditty: A for horses B for mutton, etc. E for vescences! (13) Belle 25-09-2003, 16:06 Originally posted by Carlwarker I WAS joking - it' from the old alphabet ditty: A for horses B for mutton, etc. E for vescences! (13) In actual fact, and despite appearances to the contrary, I am really quite clever, so I did know you were joking....honest ((carl)) Carlwarker 25-09-2003, 16:08 Originally posted by max (114 + 1) * 114/2 = 6555 However if he only had 114 links it would run out after 2 weeks (14 + 1) * 14/2 = 105 I think you meant 14 weeks, didn't you max? upholder 25-09-2003, 16:51 Four men in hats brain teaser. Click here for the puzzle (http://cundys.bizland.com/men.html) I first saw this years ago now it's all over the net so try and solve it without Googling the answer. You have to name the man and the reason. max 25-09-2003, 17:01 Originally posted by Carlwarker I think you meant 14 weeks, didn't you max? OK, in my haste I translated 14 to days then into weeks. The maths is OK though, isn't it? max 25-09-2003, 17:19 Originally posted by Carlwarker I WAS joking - it' from the old alphabet ditty: A for horses B for mutton, etc. E for vescences! (13) Isn't it: E for anaesthetic F for vescence max 25-09-2003, 17:25 If it's E(12) not E(13) then the answer is individually halevan 25-09-2003, 19:29 Originally posted by Carlwarker Two missiles speed directly toward each other, one at 9,000 mph and the other at 21,000 mph. The start 1,767 miles apart. Without using pencil and paper, calculate how far apart they are one minute before they collide. Come on all you Einsteins!!! John 25-09-2003, 19:47 C shout out black. If he was white D would have shouted out black long ago. Jamie 25-09-2003, 20:44 John ... what are you on about ? John 25-09-2003, 20:45 Upholder posted a problem and I've given the answer. nomme 26-09-2003, 00:07 Originally posted by max If it's E(12) not E(13) then the answer is individually Nope, it's definitely E(13). However, I'd like to hear your explaination of 'individually' for E(12) Nomme upholder 26-09-2003, 07:18 Originally posted by John C shout out black. If he was white D would have shouted out black long ago. Correct :D max 26-09-2003, 07:28 Originally posted by nommedenet Nope, it's definitely E(13). However, I'd like to hear your explaination of 'individually' for E(12) Nomme Oh well, back to the drawing board. My solution, though wrong, is: individual e nomme 26-09-2003, 09:15 Originally posted by max Oh well, back to the drawing board. My solution, though wrong, is: individual e Ah - nice one. If no one gets it I'll post the solution later today or tomorrow. Meanwhile...... This is quite a good one if you've not seen it before : Allegedly, this is one of the questions for potential Microsoft employees. I must warn you, you can really get caught up trying to solve this problem. Reportedly, one guy solved it by writing a C program, although that took him 37 minutes to develop (compiled and ran on the 1st try though). Another guy solved it in three minutes. A group of 50, at Motorola, couldn't figure it out at all. See how long it takes you. "U2" has a concert that starts in 17 minutes and they must all cross a bridge to get there. All four men begin on the same side of the bridge. You must help them across to the other side. It is night. There is one flashlight. A maximum of two people can cross at one time. Any party who crosses, either 1 or 2 people, must have the flashlight with them. The flashlight must be walked back and forth, it cannot be thrown, etc. Each band member walks at a different speed. A pair must walk together at the rate of the slower man's pace: Bono:- 1 minute to cross Edge:- 2 minutes to cross Adam:- 5 minutes to cross Larry:-10 minutes to cross For example: if Bono and Larry walk across first, 10 minutes have elapsed when they get to the other side of the bridge. If Larry then returns with the flashlight, a total of 20 minutes have passed and you have failed the mission. Notes: There is no trick behind this. It is the simple movement of resources in the appropriate order. There are two known answers to this problem. This is based on a question Microsoft gives to all prospective employees. Note: Microsoft expects you to answer this question in under 5 minutes! Don't take it too hard if you don't figure this out... (I nicked this from elsewhere - so I don't know if the stuff about microsoft is actually true or not) Belle 26-09-2003, 09:20 Originally posted by John C shout out black. If he was white D would have shouted out black long ago. That is brilliant John, I hope you didnt cheat. You are obviously very clever - and you sorted it for me ! Belle 26-09-2003, 09:24 At the moment I cant do the U2 thing in less than 19 minutes, but then I am never much good at those ones Carlwarker 26-09-2003, 10:43 Originally posted by LouiseB At the moment I cant do the U2 thing in less than 19 minutes, but then I am never much good at those ones Me too Louise, unless there's 'piggy-backing' aloud - but , I guess, that's a trick solution. And, having just awoken (11.30 am) from a heavy night, 'logic' questions seem extra difficult through the murky mists of my mind. Ah, the joys of being retired. Jamie 26-09-2003, 11:08 1+2 go across bridge (2 mins) 1 comes back (1 mins) 5+10 go cross bridge (10 mins) 2 comes back (2 mins) 1+2 go across bridge (2 mins) 17 mins total ... took about 1 minute to figure out. still working on nommedenet 's rock problem ... grrr. Belle 26-09-2003, 11:08 Well I wont give it away, but I cheated and looked on the net. As soon as I found the answer, I remembered that the answer to all these bridge crossing type thingies always works like that, and I am always crap until afterwards..........sigh Louise x Jamie 26-09-2003, 11:11 nommedenet's rock problem ... you have a 40kg lump of rock. you have some wieghing scales (like on the libra starsign). break the lump of rock up in to 4 pieces ... such that you can weigh anything between 1kg and 40kg. what are the weights of the 4 lumps? Belle 26-09-2003, 11:22 8 9 10 13 9 - 8 = 1 10 - 8 = 2 13 - 10 + 3 8 + 9 + 17 - 13 = 4 13 - 8 = 5 10 + 9 - 13 = 6 Havent bothered to work out any further up, hope that will do it It had better because I am sitting here all chuffed for finally working one out! LouiseB Jamie 26-09-2003, 11:32 I had those exact same numbers last night louise ... and i got up to 15 ... but couldn't for the life of me get 16 (was even dreaming about it). 8kg 9kg 10kg 13kg .... how do you weigh something at 16kg? Jamie 26-09-2003, 11:37 unless you can say ... it weights more than 15 ... but less that 17 ? does that count as cheating ? nomme 26-09-2003, 11:58 Originally posted by JamieW I had those exact same numbers last night louise ... and i got up to 15 ... but couldn't for the life of me get 16 (was even dreaming about it). LOL - Hey I did say don't lose any sleep over it. Nomme Belle 26-09-2003, 12:13 Originally posted by JamieW unless you can say ... it weights more than 15 ... but less that 17 ? does that count as cheating ? I dont think it would be cheating. We know our lumps are exact weight, so more than 15 but less than 17 can only be 16. I am still working on 16 (since you mentioned it) but promise not to fall asleep thinking about it Jamie 26-09-2003, 12:31 LOL ... I just thought it can't be 8 9 10 13 ... and fell asleep ... mmmm ... lovely sleep ... What do you think nomme ? More than 15 but less than 17 ... is that an ok solution to the 16 ? nomme 26-09-2003, 12:45 Originally posted by JamieW LOL ... I just thought it can't be 8 9 10 13 ... and fell asleep ... mmmm ... lovely sleep ... What do you think nomme ? More than 15 but less than 17 ... is that an ok solution to the 16 ? It would be OK in my book. I don't actually know if there is more than 1 answer, but looking at the numbers you have I'm struggling to see how you would do the high thirties, say from 34 - 40. Jamie 26-09-2003, 12:50 Good point ... certainly would be a struggle to get 39kg with the lowest chunk of rock being 8kg. In order to get 39kg ... you would need a 2kg smallest rock. i.e. less than 40 but more than 38. I am guessing that you need to use the less than 'x' but more than 'y' approach. Carlwarker 26-09-2003, 12:57 Originally posted by nommedenet It would be OK in my book. I don't actually know if there is more than 1 answer, but looking at the numbers you have I'm struggling to see how you would do the high thirties, say from 34 - 40. I'm still 'fuzzy' from last night - but how do you get any weighing above 24, except for 40? Belle 26-09-2003, 13:00 8 on one side, the rest on the other is obviously 32 9 on one side with the rest on the other is obviously 31 10 on one side with the rest on the other is obviously 30 etc You just have to keep adding and substracting until you make it work I still think this is the answer, but am open for someone to tell me an alternative Carlwarker 26-09-2003, 13:05 Thankyou LouiseB - as I said I am fuzzy - someone must have spiked my drink last night, 'coz I'm not usually THAT fuzzy. Thus, goodbye for a while friends, it's time to recuperate... max 26-09-2003, 13:18 As I read the original rocks thing the idea was to weigh anything not just the bits of rock. I took this to mean that if, for instance, you had something weighing 34kg you could add a 3kg lump to that and put the remaining 37kg of rocks on the other side. If that is the problem then it opens up another can of worms. Did anybody else read it that way? Jamie 26-09-2003, 13:19 But Louise ... How do you determine if something is 39 ? If you only have 8,9,10 and 13 ? Belle 26-09-2003, 13:20 Originally posted by max As I read the original rocks thing the idea was to weigh anything not just the bits of rock. I took this to mean that if, for instance, you had something weighing 34kg you could add a 3kg lump to that and put the remaining 37kg of rocks on the other side. If that is the problem then it opens up another can of worms. Did anybody else read it that way? Max go away and shake your head of course that is what it means you put the thing - a lump of cheese, in the scales to BALANCE THEM.........doh... Belle 26-09-2003, 13:21 Originally posted by JamieW But Louise ... How do you determine if something is 39 ? If you only have 8,9,10 and 13 ? You cant, we messed up, those numbers are wrong I have cheated and found the answer but will keep it to myself while you start again.......grrrr max 26-09-2003, 13:25 Originally posted by LouiseB Max go away and shake your head of course that is what it means you put the thing - a lump of cheese, in the scales to BALANCE THEM.........doh... Oops :blush: Jamie 26-09-2003, 13:29 U cheat !!! lol Yeah that is how I understood the problem MAX. I think you need to work out the smallest size rock u will need to weigh something at 39. I recon this would be a 2kg rock. I think you need to use the more than x and less than y thingy too. Carlwarker 26-09-2003, 13:33 I think I have recuperated - try 1, 3, 9 and 27. max 26-09-2003, 13:41 Originally posted by Carlwarker I think I have recuperated - try 1, 3, 9 and 27. Yup, that works. Nice one. Next puzzle please! Jamie 26-09-2003, 13:42 Nice one Carl ... that seems to do the trick ! 1,3 and 9 can do anything up to 13 27 - 13 = 14 27 - 12 = 15 : 27 - 2 = 25 27 - 1 = 26 27 = 27 27 + 1 = 28 27 + 2 = 29 : 27 + 12 = 39 27 + 13 = 40 Carlwarker 26-09-2003, 13:50 Also interesting is that they are the first four powers of 3 (3 to the zero ... 3 cubed). nomme 26-09-2003, 13:54 Originally posted by JamieW Nice one Carl ... that seems to do the trick ! 1,3 and 9 can do anything up to 13 27 - 13 = 14 27 - 12 = 15 : 27 - 2 = 25 27 - 1 = 26 27 = 27 27 + 1 = 28 27 + 2 = 29 : 27 + 12 = 39 27 + 13 = 40 Yes well done Carlwarker. Phew - someone got it! Next time you see a set of weights take a look a the sequence they take.... 1,2,4,8,16,32 ,64 etc...... cf 1,3,9,27 cheers Nomme Belle 26-09-2003, 13:56 So I DIDNT get it after all wipes smirk off own face :( Try me with something else then, useless ol' me Jamie 26-09-2003, 13:59 Oh well Louise hunni ... at least someone else was barking up the same wrong tree as you *blushes* lol nomme 26-09-2003, 14:00 Originally posted by LouiseB So I DIDNT get it after all wipes smirk off own face :( Try me with something else then, useless ol' me Nevermind try this one. Explain this : A man walks into a bar and asks the barman for a glass of water. The barman pulls out a gun and points it at the man. The man says 'Thank you' and walks out. Nomme Belle 26-09-2003, 14:01 Originally posted by nommedenet Nevermind try this one. Explain this : A man walks into a bar and asks the barman for a glass of water. The barman pulls out a gun and points it at the man. The man says 'Thank you' and walks out. Nomme I know that one already but thanks for trying for me It is Fab isnt it Jamie 26-09-2003, 14:04 Gus is a water pistol ? nomme 26-09-2003, 14:10 Originally posted by JamieW Gus is a water pistol ? No it's a real gun. Nomme nomme 26-09-2003, 14:11 Originally posted by LouiseB I know that one already but thanks for trying for me It is Fab isnt it Doh! How about this one: One day Jill celebrated her birthday. Two days later her older twin brother, Jack, celebrated his birthday. How come? Nomme Belle 26-09-2003, 14:14 Originally posted by nommedenet Doh! How about this one: One day Jill celebrated her birthday. Two days later her older twin brother, Jack, celebrated his birthday. How come? Nomme I know that one as well sorry, try a different website, I think I went there yesterday Belle 26-09-2003, 14:16 Originally posted by JamieW Gus is a water pistol ? Jamie, it is easy if you take it in stages. I wont give you a clue, but, start at the beginning The man asks for a glass of water..........why would he want a glass of water? Then you are there in seconds.....I worked it out yesterday when I was on the same website Nomme is now on I imagine. Sadly it means I will know them all.....sigh Carlwarker 26-09-2003, 14:35 Originally posted by nommedenet Yes well done Carlwarker. Phew - someone got it! Next time you see a set of weights take a look a the sequence they take.... 1,2,4,8,16,32 ,64 etc...... cf 1,3,9,27 cheers Nomme Regarding the binary system, it’s interesting that, although Liebnitz is credited with it’s ‘discovery’ in the West, he was aware, through his contact with Pere Bouvet ( a Jesuit missionary and mathematician in China), of Fu Hsi’s arrangement of the hexagrams of the I Ching ( about 3000 BC) – the first known ‘counting’ in the binary system (0 – 63 in decimal numeration). I know it doesn’t change (no pun) the price of bread, but … nomme 26-09-2003, 14:52 Originally posted by LouiseB Sadly it means I will know them all.....sigh Grrr! My last go then. No cheatin' !!! Which letter is missing from this sequence :..... A, A, A, A, *?* A, A, A, A, A, A Note: the answer is not A. Nomme Belle 26-09-2003, 15:15 W for Watling Street, the A5? weak I know...........thinking......... Carlwarker 26-09-2003, 15:39 H? Ha ha ha. nomme 26-09-2003, 15:42 Originally posted by Carlwarker H? Ha ha ha. Nope. Louise - its not 'w' either. Nomme Carlwarker 26-09-2003, 16:05 Some kind of synonym for 5'A's? Carlwarker 26-09-2003, 16:09 Or is it the answer to the old riddle: When is a door not a door? When it's aaaajaaaaaa! |